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📐 AI MathID: vector-spaces

Vector Spaces & Fundamental Subspaces

向量空间与四大子空间
🎯Core Definition
A vector space is a set closed under addition and scalar multiplication; a subspace is a nonempty subset containing zero and closed under linear combinations. A matrix ARm×nA \in \mathbb{R}^{m \times n} induces four fundamental subspaces: the column space C(A)RmC(A) \subseteq \mathbb{R}^m, the null space N(A)RnN(A) \subseteq \mathbb{R}^n, the row space C(AT)RnC(A^T) \subseteq \mathbb{R}^n, and the left null space N(AT)RmN(A^T) \subseteq \mathbb{R}^m. The rank-nullity theorem gives the dimension relations dimC(A)=dimC(AT)=r=rank(A)\dim C(A) = \dim C(A^T) = r = \text{rank}(A), dimC(A)+dimN(A)=n\dim C(A) + \dim N(A) = n, and dimC(A)+dimN(AT)=m\dim C(A) + \dim N(A^T) = m; moreover N(A)N(A) is the orthogonal complement of C(AT)C(A^T) in Rn\mathbb{R}^n, and N(AT)N(A^T) the orthogonal complement of C(A)C(A) in Rm\mathbb{R}^m. Intuition: the row space carries where information comes from, the null space is the set of directions crushed to zero, and the two orthogonally split the input space.
💡Use Cases
deciding whether Ax=bAx = b is solvable and the dimension of its solution set; the projection geometry of least squares; the theoretical foundation of SVD, pseudoinverse and rank analysis; principal directions in PCA live in the row space; often the opening question of derivation-focused interviews.
Key Problems Solved
it translates "does a solution exist / is it unique" into subspace containment: Ax=bAx = b is solvable iff bC(A)b \in C(A), and every solution equals a particular solution plus a vector from N(A)N(A), so the solution is unique iff N(A)={0}N(A) = \{0\} (full column rank, r=nr = n); the orthogonal decompositions Rn=C(AT)N(A)\mathbb{R}^n = C(A^T) \oplus N(A) and Rm=C(A)N(AT)\mathbb{R}^m = C(A) \oplus N(A^T) supply the geometric framework for approximating unsolvable systems (least squares).
🎯5 High-Frequency Exam Points
1
By hand: for a concrete matrix (e.g. 2×3), write bases and dimensions of all four fundamental subspaces and verify rank-nullity.
2
State the dimension relations dimC(A)+dimN(A)=n\dim C(A) + \dim N(A) = n and dimC(A)+dimN(AT)=m\dim C(A) + \dim N(A^T) = m; which ambient space does each term live in?
3
Prove N(AT)=C(A)N(A^T) = C(A)^\perp and show every yRmy \in \mathbb{R}^m splits uniquely into a C(A)C(A) part plus an N(AT)N(A^T) part.
4
Derive why a unique solution to Ax=bAx = b is equivalent to N(A)={0}N(A) = \{0\}; demonstrate no-solution, unique-solution, and infinite-solution cases with 2×2 examples.
5
Why is rank(A)=rank(AT)\text{rank}(A) = \text{rank}(A^T)? Derive it fully from N(A)=C(AT)N(A) = C(A^T)^\perp and the rank-nullity theorem.
📖 In-depth Guide:📄 linear-algebra-for-ai
Updated 2026-08-12
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